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core/passphrase: show dialog to enter the passphrase on host

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Tomas Susanka 2020-01-23 12:31:02 +00:00 committed by Pavol Rusnak
parent a3f3d4fcdb
commit 8fa0d8f098
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1 changed files with 14 additions and 0 deletions
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14
core/src/apps/common/passphrase.py
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@ -7,7 +7,10 @@ from trezor.messages.ButtonAck import ButtonAck
from trezor.messages.ButtonRequest import ButtonRequest
from trezor.messages.PassphraseAck import PassphraseAck
from trezor.messages.PassphraseRequest import PassphraseRequest
from trezor.ui import ICON_CONFIG
from trezor.ui.passphrase import CANCELLED, PassphraseKeyboard
from trezor.ui.popup import Popup
from trezor.ui.text import Text
if __debug__:
from apps.debug import input_signal
@ -38,6 +41,8 @@ async def _get_from_user(ctx: wire.Context) -> str:
if storage.device.get_passphrase_always_on_device():
return await request_from_user_on_device(ctx)
await _entry_dialog()
request = PassphraseRequest()
ack = await ctx.call(request, PassphraseAck)
if ack.on_device:
@ -66,3 +71,12 @@ async def request_from_user_on_device(ctx: wire.Context) -> str:
assert isinstance(passphrase, str)
return passphrase
async def _entry_dialog() -> None:
text = Text("Passphrase entry", ICON_CONFIG)
text.normal("Please type your", "passphrase on the", "connected host.")
# no need to specify timeout, because it hangs till PassphraseAck is received
# TODO ask: not sure this is correct. If we change the behaviour of Popup
# (e.g. to be redrawn after the timeout expires) this will no longer display the dialog
await Popup(text)