ed25519: type hints

pull/25/head
matejcik 6 years ago
parent 2fdb5cd538
commit 0e8fe9e743

@ -2,17 +2,20 @@
# modified for Python 3 by Jochen Hoenicke <hoenicke@gmail.com>
import hashlib
from typing import Tuple, NewType
Point = NewType("Point", Tuple[int, int])
b = 256
q = 2 ** 255 - 19
l = 2 ** 252 + 27742317777372353535851937790883648493
def H(m):
def H(m: bytes) -> bytes:
return hashlib.sha512(m).digest()
def expmod(b, e, m):
def expmod(b: int, e: int, m: int) -> int:
if e < 0:
raise ValueError('negative exponent')
if e == 0:
@ -23,7 +26,7 @@ def expmod(b, e, m):
return t
def inv(x):
def inv(x: int) -> int:
return expmod(x, q - 2, q)
@ -31,7 +34,7 @@ d = -121665 * inv(121666)
I = expmod(2, (q - 1) >> 2, q)
def xrecover(y):
def xrecover(y: int) -> int:
xx = (y * y - 1) * inv(d * y * y + 1)
x = expmod(xx, (q + 3) >> 3, q)
if (x * x - xx) % q != 0:
@ -43,22 +46,22 @@ def xrecover(y):
By = 4 * inv(5)
Bx = xrecover(By)
B = [Bx % q, By % q]
B = Point((Bx % q, By % q))
def edwards(P, Q):
def edwards(P: Point, Q: Point) -> Point:
x1 = P[0]
y1 = P[1]
x2 = Q[0]
y2 = Q[1]
x3 = (x1 * y2 + x2 * y1) * inv(1 + d * x1 * x2 * y1 * y2)
y3 = (y1 * y2 + x1 * x2) * inv(1 - d * x1 * x2 * y1 * y2)
return [x3 % q, y3 % q]
return Point((x3 % q, y3 % q))
def scalarmult(P, e):
def scalarmult(P: Point, e: int) -> Point:
if e == 0:
return [0, 1]
return Point((0, 1))
Q = scalarmult(P, e >> 1)
Q = edwards(Q, Q)
if e & 1:
@ -66,35 +69,35 @@ def scalarmult(P, e):
return Q
def encodeint(y):
def encodeint(y: int) -> bytes:
bits = [(y >> i) & 1 for i in range(b)]
return bytes([sum([bits[i * 8 + j] << j for j in range(8)]) for i in range(b >> 3)])
def encodepoint(P):
def encodepoint(P: Point) -> bytes:
x = P[0]
y = P[1]
bits = [(y >> i) & 1 for i in range(b - 1)] + [x & 1]
return bytes([sum([bits[i * 8 + j] << j for j in range(8)]) for i in range(b >> 3)])
def bit(h, i):
def bit(h: bytes, i: int) -> int:
return (h[i >> 3] >> (i & 7)) & 1
def publickey(sk):
def publickey(sk: bytes) -> bytes:
h = H(sk)
a = 2 ** (b - 2) + sum(2 ** i * bit(h, i) for i in range(3, b - 2))
A = scalarmult(B, a)
return encodepoint(A)
def Hint(m):
def Hint(m: bytes) -> int:
h = H(m)
return sum(2 ** i * bit(h, i) for i in range(2 * b))
def signature(m, sk, pk):
def signature(m: bytes, sk: bytes, pk: bytes) -> bytes:
h = H(sk)
a = 2 ** (b - 2) + sum(2 ** i * bit(h, i) for i in range(3, b - 2))
r = Hint(bytes([h[i] for i in range(b >> 3, b >> 2)]) + m)
@ -103,28 +106,28 @@ def signature(m, sk, pk):
return encodepoint(R) + encodeint(S)
def isoncurve(P):
def isoncurve(P: Point) -> bool:
x = P[0]
y = P[1]
return (-x * x + y * y - 1 - d * x * x * y * y) % q == 0
def decodeint(s):
def decodeint(s: bytes) -> int:
return sum(2 ** i * bit(s, i) for i in range(0, b))
def decodepoint(s):
def decodepoint(s: bytes) -> Point:
y = sum(2 ** i * bit(s, i) for i in range(0, b - 1))
x = xrecover(y)
if x & 1 != bit(s, b - 1):
x = q - x
P = [x, y]
P = Point((x, y))
if not isoncurve(P):
raise ValueError('decoding point that is not on curve')
return P
def checkvalid(s, m, pk):
def checkvalid(s: bytes, m: bytes, pk: bytes) -> None:
if len(s) != b >> 2:
raise ValueError('signature length is wrong')
if len(pk) != b >> 3:

Loading…
Cancel
Save