Fixed strategy for eliminating hashes with zero length in LM when multiple hashes contain a zero hash

docs/changes.txt

@@ -13,6 +13,7 @@
 - Fixed division by zero because backend_ctx->hardware_power_all was not re-inserted after refactoring device_param->hardware_power
 - Fixed invalid progress counter initialization in attack-mode 9 when using --skip or --restore
 - Fixed out-of-boundary reads in attack-mode 9 that were caused by a missing work item limit in the refactored autotune engine
+- Fixed strategy for eliminating hashes with zero length in LM when multiple hashes contain a zero hash
 
 ##
 ## Technical

src/hashes.c

@@ -2263,14 +2263,18 @@ int hashes_init_zerohash (hashcat_ctx_t *hashcat_ctx)
 
   module_ctx->module_hash_decode_zero_hash (hashconfig, hash_buf.digest, hash_buf.salt, hash_buf.esalt, hash_buf.hook_salt, hash_buf.hash_info);
 
-  hash_t *found = (hash_t *) hc_bsearch_r (&hash_buf, hashes_buf, hashes_cnt, sizeof (hash_t), sort_by_hash_no_salt, (void *) hashconfig);
+  for (u32 i = 0; i < hashes_cnt; i++)
+  {
+    hash_t *next = &hashes_buf[i];
+
+    int rc = sort_by_hash_no_salt (&hash_buf, next, (void *) hashconfig);
 
-  if (found != NULL)
+    if (rc == 0)
     {
-    found->pw_buf = (char *) hcmalloc (1);
-    found->pw_len = 0;
+      next->pw_buf = (char *) hcmalloc (1);
+      next->pw_len = 0;
 
-    found->cracked = 1;
+      next->cracked = 1;
 
       // should we show the cracked zero hash to the user?
 
@@ -2278,7 +2282,7 @@ int hashes_init_zerohash (hashcat_ctx_t *hashcat_ctx)
       {
         // digest pos
 
-      const u32 digest_pos = found - hashes_buf;
+        const u32 digest_pos = next - hashes_buf;
 
         // show the crack
 
@@ -2310,6 +2314,7 @@ int hashes_init_zerohash (hashcat_ctx_t *hashcat_ctx)
         hcfree (out_buf);
       }
     }
+  }
 
   if (hashconfig->esalt_size > 0)
   {