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14138a859f
Also print() function, ternary if, avoid backslashes.
57 lines
1.8 KiB
Python
57 lines
1.8 KiB
Python
import ecdsa
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import os
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# secp256k1, http://www.oid-info.com/get/1.3.132.0.10
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_p = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEFFFFFC2F
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_r = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364141
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_b = 0x0000000000000000000000000000000000000000000000000000000000000007
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_a = 0x0000000000000000000000000000000000000000000000000000000000000000
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_Gx = 0x79BE667EF9DCBBAC55A06295CE870B07029BFCDB2DCE28D959F2815B16F81798
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_Gy = 0x483ada7726a3c4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8
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curve_secp256k1 = ecdsa.ellipticcurve.CurveFp(_p, _a, _b)
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generator_secp256k1 = ecdsa.ellipticcurve.Point(curve_secp256k1, _Gx, _Gy, _r)
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oid_secp256k1 = (1, 3, 132, 0, 10)
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SECP256k1 = ecdsa.curves.Curve("SECP256k1", curve_secp256k1,
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generator_secp256k1, oid_secp256k1)
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ec_order = _r
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curve = curve_secp256k1
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generator = generator_secp256k1
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def random_secret():
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convert_to_int = lambda array: int("".join(array).encode("hex"), 16)
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# Collect 256 bits of random data from the OS's cryptographically secure
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# random generator
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byte_array = os.urandom(32)
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return convert_to_int(byte_array)
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def get_point_pubkey(point):
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key = ('03' if point.y() & 1 else '02') + '%064x' % point.x()
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return key.decode('hex')
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def get_point_pubkey_uncompressed(point):
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key = ('04' +
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'%064x' % point.x() +
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'%064x' % point.y())
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return key.decode('hex')
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# Generate a new private key.
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secret = random_secret()
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print("Secret: ", secret)
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# Get the public key point.
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point = secret * generator
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print("EC point:", point)
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print("BTC public key:", get_point_pubkey(point).encode("hex"))
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# Given the point (x, y) we can create the object using:
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point1 = ecdsa.ellipticcurve.Point(curve, point.x(), point.y(), ec_order)
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assert(point1 == point)
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