Edited ch10.asciidoc with Atlas code editor

ch10.asciidoc

@@ -605,40 +605,38 @@ As you can see, there are a lot of zeros at the beginning of that target, meanin
 
 The formula to calculate the difficulty target from this representation is:
 
-
-target = coefficient * 2^(8*(exponent–3))^
-
+++++
+<ul class="simplelist">
+  <li>target = coefficient * 2<sup>(8*(exponent–3))</sup></li>
+</ul>
+++++
 
 Using that formula, and the difficulty bits value 0x1903a30c, we get:
 
-
-
-target = 0x03a30c * 2^0x08*(0x19-0x03)^
-
-
-=> target = 0x03a30c * 2^(0x08*0x16)^
-
-
-=> target = 0x03a30c * 2^0xB0^
-
+++++
+<ul class="simplelist">
+  <li>target = 0x03a30c * 2<sup>0x08*(0x19-0x03)</sup></li>
+  <li>=> target = 0x03a30c * 2<sup>(0x08*0x16)</sup></li>
+  <li>=> target = 0x03a30c * 2<sup>0xB0</sup></li>
+</ul>
+++++
 
 which in decimal is:
 
-
-
-=> target = 238,348 * 2^176^
-
-
-=> target = 22,829,202,948,393,929,850,749,706,076,701,368,331,072,452,018,388,575,715,328
-
+++++
+<ul class="simplelist">
+  <li>=> target = 238,348 * 2<sup>176</sup></li>
+  <li>=> target = 22,829,202,948,393,929,850,749,706,076,701,368,331,072,452,018,388,575,715,328</li>
+</ul>
+++++
 
 switching back to hexadecimal:
 
-
-
-=> target = 0x0000000000000003A30C00000000000000000000000000000000000000000000
-
-
+++++
+<ul class="simplelist">
+  <li>=> target = 0x0000000000000003A30C00000000000000000000000000000000000000000000</li>
+</ul>
+++++
 
 This means that a valid block for height 277,316 is one that has a block header hash that is less than the target. In binary that number must have more than 60 leading bits set to zero. With this level of difficulty, a single miner processing 1 trillion hashes per second (1 terahash per second or 1 TH/sec) would only find a solution once every 8,496 blocks or once every 59 days, on average.