From 7b3540f49993f0464737090fff99b5b553180b7f Mon Sep 17 00:00:00 2001 From: "Andreas M. Antonopoulos" Date: Mon, 23 Feb 2015 20:08:58 -0500 Subject: [PATCH] Addressing 152282 --- ch04.asciidoc | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/ch04.asciidoc b/ch04.asciidoc index b078369f..24c7b8ce 100644 --- a/ch04.asciidoc +++ b/ch04.asciidoc @@ -170,7 +170,7 @@ In some cases (i.e., if P~1~ and P~2~ have the same x values but different y val If P~1~ is the "point at infinity," then the sum P~1~ + P~2~ = P~2~. Similary, if P~2~ is the point at infinity, then P~1~ + P~2~ = P~1~. This shows how the point at infinity plays the role of 0. -It turns out that pass:[+] is associative, which means that (A+B)+C = A+(B+C). That means we can write A+B+C without parentheses without any ambiguity. +It turns out that pass:[+] is associative, which means that (A pass:[+] B) pass:[+] C = A pass:[+] (B pass:[+] C). That means we can write A pass:[+] B pass:[+] C without parentheses without any ambiguity. Now that we have defined addition, we can define multiplication in the standard way that extends addition. For a point P on the elliptic curve, if k is a whole number, then kP = P + P + P + ... + P (k times). Note that k is sometimes confusingly called an "exponent" in this case.(((range="endofrange", startref="ix_ch04-asciidoc5")))(((range="endofrange", startref="ix_ch04-asciidoc4")))