arno/bitcoinbook
1
0
Fork 0
mirror of https://github.com/bitcoinbook/bitcoinbook synced 2024-11-14 03:48:58 +00:00
Code Issues Releases Wiki Activity

Merge pull request #129 from sritchie/patch-1

Browse Source 
Small typo re: x axis reflection
This commit is contained in:
Minh T. Nguyen 2014-08-29 09:00:26 -07:00
commit 66c571bbc9
1 changed files with 1 additions and 1 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

2
ch04.asciidoc
View File

@ -212,7 +212,7 @@ y = 07CF33DA18...505BDB
To visualize multiplication of a point with an integer, we will use the simpler elliptic curve over the real numbers -- remember, the math is the same. Our goal is to find the multiple kG of the generator point G. That is the same as adding G to itself, k times in a row. In elliptic curves, adding a point to itself is the equivalent of drawing a tangent line on the point and finding where it intersects the curve again, then reflecting that point on the x-axis.
Starting with the generator point G, we take the tangent of the curve at G until it crosses the curve again at another point. This new point is -2G. Reflecting that point across the x-axis gives us 2G. If we take the tangent at 2G, it crosses the curve at -4G, which again we reflect on the x-axis to find G. Continuing this process, we can bounce around the curve finding the multiples of G, 2G, 4G, 8G, etc. As you can see, a randomly selected large number k, when multiplied against the generator point G is like bouncing around the curve k times, until we land on the point kG which is the public key. This process is irreversible, meaning that it is infeasible to find the factor k (the secret k) in any way other than trying all multiples of G (1G, 2G, 4G, etc) in a brute-force search for k. Since k can be an enormous number, that brute-force search would take an infeasible amount of computation and time.
Starting with the generator point G, we take the tangent of the curve at G until it crosses the curve again at another point. This new point is -2G. Reflecting that point across the x-axis gives us 2G. If we take the tangent at 2G, it crosses the curve at -4G, which again we reflect on the x-axis to find 4G. Continuing this process, we can bounce around the curve finding the multiples of G, 2G, 4G, 8G, etc. As you can see, a randomly selected large number k, when multiplied against the generator point G is like bouncing around the curve k times, until we land on the point kG which is the public key. This process is irreversible, meaning that it is infeasible to find the factor k (the secret k) in any way other than trying all multiples of G (1G, 2G, 4G, etc) in a brute-force search for k. Since k can be an enormous number, that brute-force search would take an infeasible amount of computation and time.