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Trailing L not needed in Py2 & Syntax Error in Py3

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Also print() function, ternary if, avoid backslashes.
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cclauss 2017-08-24 19:07:00 +02:00 committed by GitHub
parent b80cd6dbc5
commit 14138a859f
1 changed files with 23 additions and 23 deletions
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42
code/ec-math.py
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@ -1,56 +1,56 @@
import ecdsa
import os
from ecdsa.util import string_to_number, number_to_string
# secp256k1, http://www.oid-info.com/get/1.3.132.0.10
_p = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEFFFFFC2FL
_r = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364141L
_b = 0x0000000000000000000000000000000000000000000000000000000000000007L
_a = 0x0000000000000000000000000000000000000000000000000000000000000000L
_Gx = 0x79BE667EF9DCBBAC55A06295CE870B07029BFCDB2DCE28D959F2815B16F81798L
_Gy = 0x483ada7726a3c4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8L
_p = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEFFFFFC2F
_r = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364141
_b = 0x0000000000000000000000000000000000000000000000000000000000000007
_a = 0x0000000000000000000000000000000000000000000000000000000000000000
_Gx = 0x79BE667EF9DCBBAC55A06295CE870B07029BFCDB2DCE28D959F2815B16F81798
_Gy = 0x483ada7726a3c4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8
curve_secp256k1 = ecdsa.ellipticcurve.CurveFp(_p, _a, _b)
generator_secp256k1 = ecdsa.ellipticcurve.Point(curve_secp256k1, _Gx, _Gy, _r)
oid_secp256k1 = (1, 3, 132, 0, 10)
SECP256k1 = ecdsa.curves.Curve("SECP256k1", curve_secp256k1, generator_secp256k1, oid_secp256k1)
SECP256k1 = ecdsa.curves.Curve("SECP256k1", curve_secp256k1,
generator_secp256k1, oid_secp256k1)
ec_order = _r
curve = curve_secp256k1
generator = generator_secp256k1
def random_secret():
convert_to_int = lambda array: int("".join(array).encode("hex"), 16)
# Collect 256 bits of random data from the OS's cryptographically secure random generator
# Collect 256 bits of random data from the OS's cryptographically secure
# random generator
byte_array = os.urandom(32)
return convert_to_int(byte_array)
def get_point_pubkey(point):
if point.y() & 1:
key = '03' + '%064x' % point.x()
else:
key = '02' + '%064x' % point.x()
key = ('03' if point.y() & 1 else '02') + '%064x' % point.x()
return key.decode('hex')
def get_point_pubkey_uncompressed(point):
key = '04' + \
'%064x' % point.x() + \
'%064x' % point.y()
key = ('04' +
'%064x' % point.x() +
'%064x' % point.y())
return key.decode('hex')
# Generate a new private key.
secret = random_secret()
print "Secret: ", secret
print("Secret: ", secret)
# Get the public key point.
point = secret * generator
print "EC point:", point
print("EC point:", point)
print "BTC public key:", get_point_pubkey(point).encode("hex")
print("BTC public key:", get_point_pubkey(point).encode("hex"))
# Given the point (x, y) we can create the object using:
point1 = ecdsa.ellipticcurve.Point(curve, point.x(), point.y(), ec_order)
assert point1 == point
assert(point1 == point)