Trailing L not needed in Py2 & Syntax Error in Py3

Also print() function, ternary if, avoid backslashes.

code/ec-math.py

@@ -1,56 +1,56 @@
 import ecdsa
 import os
-from ecdsa.util import string_to_number, number_to_string
 
 # secp256k1, http://www.oid-info.com/get/1.3.132.0.10
-_p = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEFFFFFC2FL
+_p = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEFFFFFC2F
-_r = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364141L
+_r = 0xFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEBAAEDCE6AF48A03BBFD25E8CD0364141
-_b = 0x0000000000000000000000000000000000000000000000000000000000000007L
+_b = 0x0000000000000000000000000000000000000000000000000000000000000007
-_a = 0x0000000000000000000000000000000000000000000000000000000000000000L
+_a = 0x0000000000000000000000000000000000000000000000000000000000000000
-_Gx = 0x79BE667EF9DCBBAC55A06295CE870B07029BFCDB2DCE28D959F2815B16F81798L
+_Gx = 0x79BE667EF9DCBBAC55A06295CE870B07029BFCDB2DCE28D959F2815B16F81798
-_Gy = 0x483ada7726a3c4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8L
+_Gy = 0x483ada7726a3c4655da4fbfc0e1108a8fd17b448a68554199c47d08ffb10d4b8
 curve_secp256k1 = ecdsa.ellipticcurve.CurveFp(_p, _a, _b)
 generator_secp256k1 = ecdsa.ellipticcurve.Point(curve_secp256k1, _Gx, _Gy, _r)
 oid_secp256k1 = (1, 3, 132, 0, 10)
-SECP256k1 = ecdsa.curves.Curve("SECP256k1", curve_secp256k1, generator_secp256k1, oid_secp256k1) 
+SECP256k1 = ecdsa.curves.Curve("SECP256k1", curve_secp256k1,
+                               generator_secp256k1, oid_secp256k1)
 ec_order = _r
 
 curve = curve_secp256k1
 generator = generator_secp256k1
 
+
 def random_secret():
     convert_to_int = lambda array: int("".join(array).encode("hex"), 16)
-    
+
-    # Collect 256 bits of random data from the OS's cryptographically secure random generator
+    # Collect 256 bits of random data from the OS's cryptographically secure
+    # random generator
     byte_array = os.urandom(32)
-    
+
     return convert_to_int(byte_array)
 
+
 def get_point_pubkey(point):
-    if point.y() & 1:
+    key = ('03' if point.y() & 1 else '02') + '%064x' % point.x()
-        key = '03' + '%064x' % point.x()
-    else:
-        key = '02' + '%064x' % point.x()
     return key.decode('hex')
 
+
 def get_point_pubkey_uncompressed(point):
-    key = '04' + \
+    key = ('04' +
-          '%064x' % point.x() + \
+           '%064x' % point.x() +
-          '%064x' % point.y()
+           '%064x' % point.y())
     return key.decode('hex')
 
 
 # Generate a new private key.
 secret = random_secret()
-print "Secret: ", secret
+print("Secret: ", secret)
 
 # Get the public key point.
 point = secret * generator
-print "EC point:", point
+print("EC point:", point)
 
-print "BTC public key:", get_point_pubkey(point).encode("hex")
+print("BTC public key:", get_point_pubkey(point).encode("hex"))
 
 # Given the point (x, y) we can create the object using:
 point1 = ecdsa.ellipticcurve.Point(curve, point.x(), point.y(), ec_order)
-assert point1 == point
+assert(point1 == point)
-