6bc5671491
Apply: git diff --full-index --binary anaconda-23.19.10-1..anaconda-25.20.9-1 And resolve conflicts. QubesOS/qubes-issues#2574
42 lines
2.0 KiB
Python
42 lines
2.0 KiB
Python
#
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# Copyright (C) 2015 Red Hat, Inc.
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#
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU Lesser General Public License as published
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# by the Free Software Foundation; either version 2.1 of the License, or
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# (at your option) any later version.
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#
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU Lesser General Public License for more details.
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#
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# You should have received a copy of the GNU Lesser General Public License
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# along with this program. If not, see <http://www.gnu.org/licenses/>.
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from gladecheck import GladeTest
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class CheckMnemonics(GladeTest):
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def checkGlade(self, glade_tree):
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"""Check for widgets with keyboard accelerators but no mnemonic"""
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# Look for labels with use-underline=True and no mnemonic-widget
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for label in glade_tree.xpath(".//object[@class='GtkLabel' and ./property[@name='use_underline' and ./text() = 'True'] and not(./property[@name='mnemonic_widget'])]"):
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# And now filter out the cases where the label actually does have a mnemonic.
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# This list is not comprehensive, probably.
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parent = label.getparent()
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# Is the label the child of a GtkButton? The button might be pretty far up there.
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# Assume widget names that end in "Button" are subclasses of GtkButton
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if parent.tag == 'child' and \
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label.xpath("ancestor::object[substring(@class, string-length(@class) - string-length('Button') + 1) = 'Button']"):
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continue
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# Is the label a GtkNotebook tab?
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if parent.tag == 'child' and parent.get('type') == 'tab' and \
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parent.getparent().get('class') == 'GtkNotebook':
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continue
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raise AssertionError("Label with accelerator and no mnemonic at %s:%d" % (label.base, label.sourceline))
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